July 24th, 2010 
admin You are responsible for planning the layout of a new parking lot for a company with 200 employees. Employees are urged to carpool. From the local chamber of commerce, you learn the “average number of workers in a daily carpool is 2.4″.
a) Explain why “2.4″ cannot be the median or mode for the “average number of workers in a daily carpool”.
b) For a variety of reasons, only 91% of the workers actually come to work each day. How many parking spaces are needed for employee parking?
c) Suppose the mean commute for each carpool is 19.6 miles with a standard deviation of 6.2 miles. If the distribution of miles commuted is normal, what is the probability that two car pools chosen at random each has a commute greater than 22 miles?
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- you are responsible for planning the layout of a new parking lot for a company with 200 employees employees are urged to carpool from the local chamber of commerce you learn the average number of workers in a daily carpool is 2 4 (5)
- suppose the mean commute for each carpool is 19 6 miles with a standard deviation of 6 2 miles if the distribution of miles commuted is normal what is the probability that two car pools chosen at random each has a commute greater than 22 miles? (2)
- you are responsible for planning the layout of a new parking lot for a company with 200 employees employees are urged to carpool from the local chamber of commerce you learn the average number of workers in a daily carpool is 2 4 a) explain why 2 4 cannot (2)
- you ate responsible for planning the layout of a new parking lot for a company with 200 employees employees are urged to carpool (1)
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a) The number of workers in a carpool is a discrete type of data that can only take on values like 1, 2, 3, … The mode would be the most commonly occurring value, so that also must be a whole number, so it can’t be 2.4. The median would be the middle value in the data set after it is ordered. If there is an odd number of values, then it would just be the one number in the middle, which is again a whole number. If there is an even number of values, then you would take the average of the numbers in the middle which will either yield a whole number (like the average of 3 and 3) or will be something like 2.5 (like the average of 2 and 3). There would either be no decimal or a 5 in the tenths digit as its only decimal. So again, in this case, 2.4 is not possible.
b) This means that 200(0.91) = 182 people come to work every day. If you assume that 2.4 average in each car, then the number of cars can be calculated.
mean = number of people / number of cars
2.4 = 182/n
=> n = 182/2.4 = 75.83 cars, so you would need 76 spaces.
c) First find z.
z = (22-19.6)/6.2 = 0.39
Using the normal table, the area above 22 is 0.3483. Since each car has the probability, and assuming independence, you would multiply because it’s an “and” probability.
P(1st is > 22 and 2nd is > 22) = 0.3483^2 = 0.1213